SOLUTION: If a plane is flying at an altitude of 500m and the bottle lands 400m horizontally from the initial dropping point, how fast was the plane flying when the bottle was released.
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Question 216616: If a plane is flying at an altitude of 500m and the bottle lands 400m horizontally from the initial dropping point, how fast was the plane flying when the bottle was released.
-Physics-
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
The vertical drop is only related to the height and gravity by,
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d= 1/2 gt^2,,,,where d=distance (m),,,g=9.81 (m / sec^2),,, and t=time (sec)
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500 m = 1/2 *9.81 *t^2
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500*2/9.81 = 101.936 sec^2 = t^2
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10.0964 sec = t,,,,
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the velocity of the plane in that time is distance / time
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v=d/t = 400/10.0964 = 39.618 m/sec
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