SOLUTION: s+{2s-1}+{3s-4}=37
Algebra.Com
Question 216169: s+{2s-1}+{3s-4}=37
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
s+{2s-1}+{3s-4}=37
6s-5=37
6s=37+5
6s=42
s=42/6
s=7 ans.
Proof:
7+2*7-1+3*7-4=37
7+14-1+21-4=37
42-5=37
37=37
RELATED QUESTIONS
Suzy buys 2 shirts and 2 pairs of pants for 42 dollars at the store. Annette buys 3... (answered by addingup)
Simplify... (answered by jim_thompson5910)
fractions
1/3s=7/9=4/3s
1/3s= -7/9+4/3s
1/3s-4/3s=-7/9
-s=-7/9
is this... (answered by drk)
-2s + 6 = -5s + 12
+2s +2s
6 = -3s + 12
- 12 - 12
- 6 = -3s
(answered by Diana541)
Can you help me find the Nth term of this arihmetic sequence?
4, 4+s, 4+2s,... (answered by vksarvepalli)
2|4-s|=-3s (answered by ReadingBoosters,MathTherapy)
2s(s-4) (answered by fractalier)
3s+2s-1s (answered by sdmmadam@yahoo.com)
Simplify, the equation and give your answers with positive powers only.
(r-^1/3s^2) /... (answered by Alan3354)