SOLUTION: Suppose that the length of a certain rectangle is 9 meters less than two times its width. The perimeter of the rectangle is 42 meters. Find the length and width of the rectangle.

Question 213480: Suppose that the length of a certain rectangle is 9 meters less than two times its width. The perimeter of the rectangle is 42 meters. Find the length and width of the rectangle.
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
Suppose that the length of a certain rectangle is 9 meters less than two times its width. The perimeter of the rectangle is 42 meters. Find the length and width of the rectangle.

Step 1. Let l = 2w-9 be the length of rectangle and let w be the width

Step 2. Let P = 42 meters be the perimeter. Perimeter means adding the 4 sides of a rectangle. So,

Step 3. Add 18 to both sides of equation to get 4w by itself

Step 4. Divide 6 to both sides of equation

Step 5. w = 10 meters is the width of the rectangle and length is 11 m since

l=2w-9=11

Check P=2w+2l=2(10)+2(11)=20+22=42 So w = 10 meters and l = 11 meters is the solution.

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trig Vids please visit http://www.FreedomUniversity.TV/courses/Trigonometry

And GOOD LUCK in your studies!

Respectfully
Dr J
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