SOLUTION: 2n+3+4n=2n+5+4n-2

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Question 213089: 2n+3+4n=2n+5+4n-2
Answer by drj(1380)   (Show Source): You can put this solution on YOUR website!


The following steps simplifies the above equation.


Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • Graphical form: Equation was fully solved.
  • Text form: 2n+3+4n=2n+5+4n-2 simplifies to 0=0
  • Cartoon (animation) form:
    For tutors: simplify_cartoon( 2n+3+4n=2n+5+4n-2 )
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DETAILED EXPLANATION

Look at .
Moved 3 to the right of expression
It becomes .
Look at .
Eliminated similar terms highlight_red%28+2%2An+%29,highlight_red%28+4%2An+%29 replacing them with highlight_green%28+%282%2B4%29%2An+%29
It becomes .
Look at .
Added fractions or integers together
It becomes .
Look at .
Remove unneeded parentheses around factor highlight_red%28+6+%29
It becomes .
Look at .
Added fractions or integers together
It becomes .
Look at .
Moved 3 to the right of expression
It becomes .
Look at .
Eliminated similar terms highlight_red%28+2%2An+%29,highlight_red%28+4%2An+%29 replacing them with highlight_green%28+%282%2B4%29%2An+%29
It becomes .
Look at .
Added fractions or integers together
It becomes .
Look at .
Remove unneeded parentheses around factor highlight_red%28+6+%29
It becomes .
Look at .
Moved these terms to the left highlight_green%28+-6%2An+%29,highlight_green%28+-3+%29
It becomes .
Look at .
Added fractions or integers together
It becomes .
Look at .
Moved 0 to the right of expression
It becomes .
Look at .
Remove extraneous zero highlight_red%28+0+%29
It becomes .
Look at .
Eliminated similar terms highlight_red%28+6%2An+%29,highlight_red%28+-6%2An+%29 replacing them with highlight_green%28+%286-6%29%2An+%29
It becomes .
Look at .
Since highlight_red%28+%286-6%29%2An+%29 has zero as a factor, it should be replaced with a zero
Look at .
Added fractions or integers together
It becomes .
Result:

Universal Simplifier and Solver


Done!



I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Good luck in your studies!

Respectfully,
Dr J
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