SOLUTION: Mr. Jackons is 13 years less than 3 times as old as his son. six years ago he was 14 years more than twice as old as his son was then. Find thire age
Algebra ->
Algebra
-> Equations
-> SOLUTION: Mr. Jackons is 13 years less than 3 times as old as his son. six years ago he was 14 years more than twice as old as his son was then. Find thire age
Log On
Question 21260: Mr. Jackons is 13 years less than 3 times as old as his son. six years ago he was 14 years more than twice as old as his son was then. Find thire age Answer by Paul(988) (Show Source):
You can put this solution on YOUR website! 3x-13=-6+14+2x
3x-13=8+2x
3x-13+13=8+13+2x
3x=21+2x
3x-2x=21+2x-2x
x=21
3(21)-13=50
Hence his son is 21 and he is 50
(