SOLUTION: Solve and Check 3[x-(2-x)-2x]=3(4-x). Im getting confused on what operation to start on first. If you can please help me and explain the problem i would really appreciate it.

Question 210891This question is from textbook
: Solve and Check
3[x-(2-x)-2x]=3(4-x).
Im getting confused on what operation to start on first. If you can please help me and explain the problem i would really appreciate it. Thank you! This question is from textbook

Found 2 solutions by rfer, jim_thompson5910:
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
3(x-(2-x)-2x)=3(4-x)
3(x-2+x-2x)=12-3x
3x-6+3x-6x=12-3x
+3x+3x-6x-6=12-3x
-6=12-3x
-18=-3x
multiply through by -
18=3x
6=x
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
3[x-(2-x)-2x]=3(4-x) ... Start with the given equation.

Distribute

Distribute again.

Combine like terms on the left side.

Subtract 12 from both sides.

Combine like terms.

Divide both sides by -3 to isolate 'x'.

Reduce

Rearrange the equation

----------------------------------------------------------------------

Answer:

So the solution is

Check:

3[x-(2-x)-2x]=3(4-x) ... Start with the given equation.

3[6-(2-6)-2*6]=3(4-6) ... Plug in (ie replace each 'x' with 6)

3[6-(2-6)-12]=3(4-6) ... Multiply

3[6-(-4)-12]=3(-2) ... Combine like terms.

3[6+4-12]=3(-2) ... Rewrite -(-4) as +4

3[-2]=3(-2) ... Combine like terms.

-6=-6 ... Multiply

Since the equation is true, this verifies the solution
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