SOLUTION: 2[7-5(1-n)] + 8n = 16 + 3[6(n+1) + 3n]

Question 209064: 2[7-5(1-n)] + 8n = 16 + 3[6(n+1) + 3n]
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
2[7-5(1-n)] +8n = 16+3[6(n+1)+3n]
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Use P E M D A S,,, Parenthesis, Exponents, Multiply/Divide.lt to rt
,,,Add/Subtract,,lt to rt,,,
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2[7-5+5n] +8n = 16 + 3[6n +6 +3n]
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2[2+5n]+8n = 16 + 3[ 9n+6]
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4+10n+8n = 16 +27n +18
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4+18n = 34 +27n
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-9n = 30
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n=-30/9 = -3 1/3
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check,,,subst into original
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2[7-5(1-(-3.3))] +8(-3.3) = 16 +3[6(-3.3) +6 +3(-3.3) ]
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-56 = -56,,,,ok

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