SOLUTION: i do not know what to do on this problem.
How much 40% antifreeze solution must be mixed with a 80% antifreeze solution to produce 20 gallons of a 70% disinfectant solution? Round
Algebra.Com
Question 207844: i do not know what to do on this problem.
How much 40% antifreeze solution must be mixed with a 80% antifreeze solution to produce 20 gallons of a 70% disinfectant solution? Round answer to the nearest gallon.
? gallons 40% solution, ? gallons 80% solution
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.40x+.80(20-x)=.70*20
.40x+16-.80x=14
-.40x=14-16
-.40x=-2
x=-2/.40
x=5 gal of 40% antifreeze is used.
20-5=15 gal of 80% anti freeze is used.
[5] gallons 40% solution, [15] gallons 80% solution
Proof:
.4*5+.8*15=.7*20
2+12=14
14=14
RELATED QUESTIONS
Please help me. How do I solve this problem: How many gallons of a 60% antifreeze... (answered by richwmiller,stanbon)
How many ounces of 20% antifreeze solution must be mixed with 30 ounces of a 50%... (answered by Earlsdon)
This is the problem: How many ounces of 50% antifreeze solution must be mixed with 10oz... (answered by josmiceli)
how much pure water must be mixed
with 2 liters 40% solution of antifreeze to get a 25% (answered by richwmiller)
How many gallons of a 60% antifreeze solution must be mixed with 80 gallons of 25%... (answered by scott8148)
How much 20% antifreeze solution must be mixed with a 80% antifreeze solution to produce... (answered by Maths68)
how much 60% antifreeze solution must be mixed with a 40% antifreeze solution to produce... (answered by robertb)
How many liters of a 40% antifreeze solution must be mixed with 5 liters of a 70%... (answered by stanbon,CharlesG2)
How much pure water must be mixed with 2 liters of a 40% solution of antifreeze to get a... (answered by richwmiller)