SOLUTION: Separate 45 into two parts such that 5 times the smaller is 6 less than twice the larger

SOLUTION: Separate 45 into two parts such that 5 times the smaller is 6 less than twice the larger

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Question 20553: Separate 45 into two parts such that 5 times the smaller is 6 less than twice the larger
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let x be the smaller part of 45.
Simplify and solve for x.
Add 2x to both sides of the equation.
Divide both sides by 7.

The smaller part is 12 and the larger part is 45-12 = 33.

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