SOLUTION: factor completely: 3x^2(4x^2+1)^8 + 64x^4(4x^2+1)^7 I worked it out and I got: 268x^18 + 64x^ + 3x^2 but it doesn't sound right!!!

Question 204997: factor completely: 3x^2(4x^2+1)^8 + 64x^4(4x^2+1)^7
I worked it out and I got: 268x^18 + 64x^ + 3x^2
but it doesn't sound right!!!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
factor completely: 3x^2(4x^2+1)^8 + 64x^4(4x^2+1)^7
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There is a common factor in the two terms.
It is x^2(4x^2+1)^7
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So factor the two terms to get these two factors:
x^2(4x^2+1)^7[3(4x^2+1) + 64x^2]
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Simplify the 2nd factor to get:
---
x^2(4x^2+1)^7[12x^2 + 3 + 64x^2]
----
x^2(4x^2+1)^7[76x^2+3]
---
[(4x^2+1)^7][76x^4+3x^2]
================================
Cheers,
Stan H.
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