SOLUTION: (15ab/4)(8/9a^2b^2)= ?
(6a/8b)/(10c/12d)= ?
(2x^2+x-3/9)[(x+1)^2/2x^2+5x+3)= ?
(1/25-y^2)/(6-3y/y^2-7y+10)= ?
Thanks!
Algebra.Com
Question 203063: (15ab/4)(8/9a^2b^2)= ?
(6a/8b)/(10c/12d)= ?
(2x^2+x-3/9)[(x+1)^2/2x^2+5x+3)= ?
(1/25-y^2)/(6-3y/y^2-7y+10)= ?
Thanks!
Answer by PRMath(133) (Show Source): You can put this solution on YOUR website!
*
I won't know how to put this in nice fractions for you, so I'll explain, as best as I can, what I'm doing............
*
The 15 and the 9 can each be reduced when divided by 3. They become 5 and 3.
The 4 and the 8 can each be reduced when divided by 4. They become 1 and 2
The ab in the numerator can be canceled, but that changes the and the in the denominator to:
SO when we reduce and cancel, we get:
/ .........OR.........
NEXT QUESTION:
The above is how I am reading your question. If I am correct, then we would do that problem the way we would do any division problem when we work with fractions. In other words, when you divide with a fraction, you MULTIPLY by the reciprocal. So your problem is now........
*
The 6 and the 10 can be reduced when divided by 2. They become 3 and 5.
The 12 and the 8 can be reduced when divided by 4. They become 3 and 2.
Your problem is now............
* and this is:
NEXT QUESTION:
/*/
If I have written your problem correctly, then it can be factored like this:
/
So the (2x + 3) in the numerator can be canceled with the (2x+3) in the denominator.
The (x + 1) in the numerator can be canceled with the (x + 1) in the denominator.
That leaves you with:
I am sorry to say that your last problem I don't think I'm seeing correctly. Can you repost it, please? It's this part of the problem I'm not sure about:
(1/25-y^2)
I am not sure you have written it correctly. The second part is easily factored. The (6 - 3y) can be factored to 3(2 - y) and the can be easily factored to (y-5)(y-2). I just am not certain your first part of the problem is written correctly.
I hope this helps .......
RELATED QUESTIONS
a) {x + 3y = 42
{ x = 4y
_________________
b) { x + 16y = 24
{2x - 16y = 12
(answered by edjones)
Give the x -intercept and y -intercept of the following.
1. 4x – y = 16
2. 2x + 3y (answered by lynnlo)
linear algebra elimination method
13) 2/3x+2/5y=4/5
1/2x+2/3y=-1/2... (answered by Edwin McCravy)
How would I solve these systems?
1)x+5y=4
3x-7y=-10
2)-5x+3y=6
x-y=4
(answered by elima)
1. (2x^2 + x - 3)/9 times (x + 1)^2/(2x^2 + 5x + 3)
2. 1/(25 - y^2) divided by (6 -... (answered by richwmiller,drk)
Can you please tell me if i got these correct?
Im doing a practice test to study for my... (answered by Edwin McCravy,solver91311)
1. 2x-y=1
6x-3y=3
2. y=5x-1
y=5x+4
3. x+y=38
x=2y-25
4. -2x+5y=9
(answered by MathLover1)
I need help with these problems!!!! PLEASE i have no clue.
1. -x/6 +4 < 1
2. ADD (2b-4) (answered by Alan3354,unlockmath)
hello im a homeschool parent and i really need our help
Find the lowest common... (answered by oscargut)