# SOLUTION: solve the inequality 4k^3-6k^2(< or =)4k

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 Question 201337: solve the inequality 4k^3-6k^2(< or =)4kAnswer by RAY100(1637)   (Show Source): You can put this solution on YOUR website!4k^3 -6k^2 < = 4k . lets solve as equality first . 4k^3 -6k^2 = 4k . 4k^3 -6k^2 -4k =0 . 2k ( 2k^2 -3k -2) = 0 . 2k (2k+1)(k-2) =0 . 2k =0,,,,k=0 . 2k+1 =0,,,,k= (-1/2) . k-2 = 0,,,,k=2 . Now on number line we have,,, (-1/2),,,,(0),,,,,(2) . Now lets check if numbers before and after each of these satisfy original inequality . for x< (-1/2),,,,let x = -1,,,,-10 <= -4,,,,ok . for (-1/2) < x < 0,,,let x= (-.25),,,-.3125 <=-1,,,,not true . for 0 less than x less than 2,,,,,let x=1,,,,-2 <= 4,,,,ok . for x>2,,,,let x= 3,,,,,54<=12,,,,,not true . Therefore,,,,,x<=(-1/2),,,,,0<=x<=2,,,,,answer