SOLUTION: Would you please show me what steps I am either leaving out or doing wrong in the following equation: {{{(5x+1)/7 - (2x-6)/4 >-4}}}. My answer does not match the one in the book.

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Question 199942This question is from textbook Intermediate Algebra
: Would you please show me what steps I am either leaving out or doing wrong in the following equation: . My answer does not match the one in the book. Thank you. This question is from textbook Intermediate Algebra

Found 2 solutions by RAY100, Edwin McCravy:
Answer by RAY100(1637)   (Show Source): You can put this solution on YOUR website!
Revised due to problem statement revision
.
(5x+1) / 7 - (2x-6) / 4 > -4
.
4(5x+1) /28 - 7(2x-6)/28 > -4
.
( 20x +4 -14x +42) / 28 > -4
.
( 6x +46) / 28 > -4
.
6x + 46 > -4 * 28
.
6x +46 > -112
.
6x > -158
.
x> -26 1/3
.

Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!
Ray's solution is incorrect.
Here is the correct solution by Edwin:




We will clear of fractions.

Put parentheses around each term and write the 
 on the right as  so
that every term will be a fraction:

 

The LCD of all the denominators is 
Multiply every term through by 

 

Cancel the 7 into the 28, getting 4

 

Cancel the 4 into the 28 in the second term, getting 7

 

Multiply the  by the  on the right getting 

 

What's left is



The we remove the parentheses by distributing:













The solution set in interval notation is (,)

Edwin


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