SOLUTION: Hi guys, im just doin some revision at the moment and cant seem to do the following problems. I have write the following expressions in their simplest form.
1. 27(x^3y^4)^2 /(3x)^
Algebra.Com
Question 199696: Hi guys, im just doin some revision at the moment and cant seem to do the following problems. I have write the following expressions in their simplest form.
1. 27(x^3y^4)^2 /(3x)^2y^-5 2. (2a*(4/3)b^2c)^-3 / (a^2bc)^3
3. (9x^2y^6)^(1/2) / 3(x^3*y^9)^1/3
Im not expecting answers to all of them, but Im hoping someone can explain and show me how to do the above problems with step by step solution.
Thanks everyone, -Nick.
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
(1) {27(x^3y^4)^2 }/ [(3x)^2 y^-5]
.
(27 x^6 y^8)/ 9x^2y^-5
.
3 x^4 y^13
.
(2) { 2a* (4/3)b^2c)^(-3)} / (a^2bc^3)
.
{ (8/3ab^2c)^(-3) } / (a^2bc^3)
.
1/ { (8/3ab^2c)^3 } { a^2bc^3 }
.
27 / { 512 a^3 b^6c^3} { a^2bc^3}
.
27/(512 a^5 b^7 c^6)
.
(3) { ( 9x^2y^6)^(1/2) } / { 3 (x^3y^9)^(1/3)
.
(3xy^3) / 3 ( x y^3 ) = 1
RELATED QUESTIONS
Hi all, was just wondering if someone could show me what the correct way to complete and... (answered by Alan3354,Edwin McCravy)
Hi guys, i was wondering if someone could help me with the following question. I cant... (answered by LOL MASTER)
Hi, I am Susan I don't have question at the moment but will come back when I do. Just... (answered by lynnlo)
Hi all, I am having some trouble with vectors at the moment, I was hoping someone could... (answered by Alan3354)
Hi There
I am new to math.... and need help please... to solve how to simplify the... (answered by math_helper)
((z^3)-(z^2)-4)/(z+i) i need to work it out then state the remainder.
It's revision and... (answered by Theo)
hi! my name is josh and i need some help solving some of these radicals. i cant seem to... (answered by mananth)
Hi! I have to do a math packet over the summer and I'm having difficulty with this one... (answered by Earlsdon)
hi, I am trying to understand the powers of ten form, I have three to solve but just... (answered by ewatrrr)