SOLUTION: The product of two positive consecutive odd intgers is 5 more than 6 times the smaller integer. Find both integers.(an algebraic solution can be accepted.)

Algebra.Com
Question 197536: The product of two positive consecutive odd intgers is 5 more than 6 times the smaller integer. Find both integers.(an algebraic solution can be accepted.)
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
The product of two positive consecutive odd intgers is 5 more than 6 times the smaller integer. Find both integers
---------------
x*(x+2) = 6x+5

(x-5)*(x+1) = 0
Integers = 5 and 7

RELATED QUESTIONS

The product of two consecutive odd integers is 6 more than 5 times the smaller number,... (answered by mananth)
The product of two consecutive positive integers is 12 more than 5 times the smaller... (answered by macston)
the product of 2 consecutive odd integers is 42 more than 3 times the smaller integer.... (answered by CubeyThePenguin)
The product of two consecutive odd integers is 10 more than the square of the smaller... (answered by stanbon,drj)
find two consecutive intgers such that the square of the sum of the two integers is 11... (answered by stanbon)
what is the smallest of 3 consecutive positive integers if the product of the smaller... (answered by Edwin McCravy)
The product of two consecutive positive intergers is 27 more than 5 times the larger... (answered by CubeyThePenguin)
one third of the sum of two consecutive odd integers is 5 less than the smaller integer.... (answered by drk)
the product two positive consecutive odd integers is 23 more than 5 times in sum. Find... (answered by checkley77)