SOLUTION: I am really suffering in this class.The problem is y=3x+6 y=2x+1 where do I begin to work this problem? I'm not sure of the steps. x= y=

Question 19522: I am really suffering in this class.The problem is y=3x+6
y=2x+1 where do I begin to work this problem? I'm not sure of the steps.
x=
y=
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
You can solve this system of equations by subtracting the second equation (y = 2x+1) from the first equation (y = 3x+6) and solving for x.
y = 3x+6
-(y = 2x+1)
0 = x + 5 Subtract 5 from both sides.
x = -5 Now substitute this value of x into either of the two equations and solve for y. Take the first equation.
y = 3(-5)+6
y = -15+6
y = -9
The solution is: (-5, -9) This is the point at which the two lines, represented by the two linear equations, intersect.
Here's the graph:

RELATED QUESTIONS
graph the equation {{{ y = x - 1}}} I am not sure where to begin and end with this... (answered by Alan3354)

i am trying to find the answer to this problem but not sure where to begin... the... (answered by Theo)

i am trying to find the answer to this problem but not sure where to begin...... (answered by College Student)

i am trying to find the answer to this problem but not sure where to begin... square (answered by College Student)

i am trying to find the answer to this problem but not sure where to begin...... (answered by Alan3354,rapaljer)

i have to find the quadratic function... (answered by scott8148)

i am trying to find the answer to this problem but not sure where to begin... 81... (answered by Theo)

Hello, I am not really sure where to put this question...what topic it would fall... (answered by nerdybill,edjones)

A friend of mine asked me how this problem would work; if y varies directly with x, and... (answered by jim_thompson5910)