SOLUTION: Jim gave one-third of his jellybeans to Jack, ate two-thirds of the remainder, and had 12 left over. How many jellybeans did he have originally?

Algebra.Com
Question 193650: Jim gave one-third of his jellybeans to Jack, ate two-thirds of the remainder, and had 12 left over. How many jellybeans did he have originally?
Found 2 solutions by josmiceli, Edwin McCravy:
Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Let = the number he had originally
given:
The amount he gave to Jack =
The remainder =
Two-thirds of the remainder =
------------------
The amount he ate plus the left over beans has to
equal , so

Multiply both sides by




He originally had 54 jelly beans
check answer:
He gave Jack
He had left
He ate
There were left over
Jack's + what he ate + left overs +

OK

Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
Edwin's solution:
Jim gave one-third of his jellybeans to Jack, ate two-thirds of
the remainder, and had 12 left over. How many jellybeans did he
have originally?

The 12 he had left over at the end was the other one-third of
what he had before eating the two-thirds.  So 12 was 1/3 of 
those he had before starting eating.  So he had 3x12 or 36 before
starting to eat.

So those 36 he had before starting eating was the other 2/3 of what
he had before giving the one-third to Jack.  So since 1/3 is half
of 2/3, then he gave Jack half of 36 or 18.  So before giving those
18 to Jack, he must have had 36+18 or 54.

---

Now we check:

Jim gave one-third of his jellybeans to Jack, 

So Jim started with 54 and gave 54*1/3 or 18 of them to Jack.

That means he only had 54-18 or 36 left.

Then Jim ate two-thirds of the remainder, 

That means he ate 2/3 of 36 or 24.

So he had 36-24 or 12 left.
  
So 54 is the correct answer.

No algebra necessary!

Edwin

RELATED QUESTIONS

Bill gave one-third of his jellybeans to a friend, ate two-thirds of the remaining... (answered by verde,ans_virgo4@hotmail.com)
3 friends share a fullbag of jellybeans. Mike took 1/3 of the jellybeans in the full bag... (answered by tmarienatree)
On Monday, John put some jellybeans in the jar. On Tuesday, Peter ate 1/3 of the... (answered by math_tutor2020)
Sophia was given a box of chocolates for her birthday and ate two-thirds of them right... (answered by josgarithmetic)
Jon ate 1/3 of jellybeans ron ate 1/4 10 were left how many were them (answered by josmiceli)
The ratio of red jellybeans to yellow jellybeans is 3:4. Jerry eats 3 red jellybeans and... (answered by stanbon)
In a bag of jellybeans, 1/3 are cherry and 1/4 are licorices. If the remaining 20... (answered by rfer)
Helen paid 25 cents for a bag of jellybeans. After giving her brother half the beans,... (answered by fractalier)
Chris was given a large bag of cookies and ate one third of the cookies before stopping... (answered by josmiceli)