Question 191845: how can the number 45 be divided into two parts so that 4 times one part is 9 less than 5 times the other? Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! how can the number 45 be divided into two parts so that 4 times one part is 9 less than 5 times the other?
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Let x = first part
then
45-x = second part
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4(45-x) = 5x-9
180 - 4x = 5x-9
180 = 9x-9
189 = 9x
21 = x (first part)
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Second part:
45-x = 45-21 = 24 (second part)
