# SOLUTION: Solve application problems: There are seven times as many deaths each year by heart disease as there are deaths by accidents. Express the number of deaths each year by heart d

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 Question 191690This question is from textbook Intermediate Algebra : Solve application problems: There are seven times as many deaths each year by heart disease as there are deaths by accidents. Express the number of deaths each year by heart disease in the terms of the number of deaths by accidents. My guess is 7x ThanksThis question is from textbook Intermediate Algebra Found 2 solutions by solver91311, jojo14344:Answer by solver91311(17077)   (Show Source): You can put this solution on YOUR website! Don't guess. That's right. If x represents the number of accidents, then 7x has to be the number of heart attacks. John Answer by jojo14344(1512)   (Show Source): You can put this solution on YOUR website! If x = number of deaths by accident in a 1 year. So, 7*x = number of deaths by heart disease, being 7 times that of accidents. If we see the graph, ---> As you see, each year, there will be 1 accident equivalent to 7 deaths by heart disease. * In Year 3 , death by accidents will be x = 3 , so death by heart disease will be 7*3=21 Thank you, Jojo