SOLUTION: Could someone help me with the following problem? Problem : A quadratic funtion has its vertex at the point of (0,-5). The function passes throuhg the point (-5,2). When w

Question 189678: Could someone help me with the following problem?
Problem : A quadratic funtion has its vertex at the point of (0,-5). The function passes throuhg the point (-5,2). When written in vertex form the function is f(x)=a(x-h)^2+k. Where a = ? , h=?, and k=?
Ok, I figured out what h and k are ( h = 0 , and k = -5) but I dont know how to get a.. could someone help me.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the general vertex form.

Plug in and

Simplify

-------------------

Plug in and

Note: since the graph passes through the point (-5,2), this means that if , then (f(x) is really "y")

Square -5 to get 25

Rearrange the terms

Add 5 to both sides.

Combine like terms.

Divide both sides by 25 to isolate "a".

Rearrange the equation

---------------

Go back to the previous function

Plug in

So the function with a vertex of (0,-5) and passes through (-5,2) is
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