SOLUTION: Find an equation of the line containing the point (-2,-5) and parallel to the line 4x-5y=13. I tried to solve the above problem and came up with the following answer: -5y/5=-4x/5

Question 187172: Find an equation of the line containing the point (-2,-5) and parallel to the line 4x-5y=13.
I tried to solve the above problem and came up with the following answer:
-5y/5=-4x/5+13/5.... y=-4/5x+13/5 ...(slope=-4/5. The answer is supposed to be y=-4/5x+17/5. I don't understand where 17 came from.
Thank you for your help with this problem.
Judy
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given equation.

Subtract from both sides.

Rearrange the terms.

Divide both sides by to isolate y.

Break up the fraction.

Reduce.

We can see that the equation has a slope and a y-intercept .

Since parallel lines have equal slopes, this means that we know that the slope of the unknown parallel line is .
Now let's use the point slope formula to find the equation of the parallel line by plugging in the slope and the coordinates of the given point

.

Start with the point slope formula

Plug in , , and

Rewrite as

Rewrite as

Distribute

Multiply

Subtract 5 from both sides.

Combine like terms.

So the equation of the line parallel to that goes through the point

is .

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