SOLUTION: the area of a parallelogramis 10in. the height is 2in. more than half the base. what is the base?...... how do you find this out?!

Question 184318: the area of a parallelogramis 10in. the height is 2in. more than half the base. what is the base?...... how do you find this out?!
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
the area of a parallelogramis 10in. the height is 2in. more than half the base. what is the base?...... how do you find this out?!
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Area = base times height
Here's what is given:
A = bh = 10 (Square inches, not inches)
h = (b/2) + 2 the height is 2in. more than half the base.
Substitute for h in the Area formula
A = b*(b/2 + 2) = 10

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=96 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 2.89897948556636, -6.89897948556636. Here's your graph:

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Ignore the negative result.
b = -2 + 2sqrt(6)
b = ~2.899 inches

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