SOLUTION: to attend a wedding Barbara starts driving west from Woodstock at 80km/h. One hour later, Barbaras parents leave Woodstock and drive along the same road at 100 km/h. At what distan
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Question 184240: to attend a wedding Barbara starts driving west from Woodstock at 80km/h. One hour later, Barbaras parents leave Woodstock and drive along the same road at 100 km/h. At what distance from Woodstock will Brabaras parents pass her?
thankyou
Found 2 solutions by checkley77, ankor@dixie-net.com:
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
80T=100(T-1)
80T=100T-100
80T-100T=-100
-20T=-100
T=-100/-20
T=5 HOURS AFTER BARBARA LEAVES HER PARENTS WILL PASS HER.
PROOF:
80*5=100(5-1)
400=100*4
400=400
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
to attend a wedding Barbara starts driving west from Woodstock at 80km/h. One hour later, Barbara's parents leave Woodstock and drive along the same road at 100 km/h. At what distance from Woodstock will Barbara's parents pass her?
:
let d = distance when this occurs
:
Write a time equation: time =
:
B's time = P's time + 1 hr
= + 1
Multiply eq by 400:
400* = 400* + 400(1)
cancel out the denominators
5d = 4d + 400
5d - 4d = 400
d = 400 km from W.
:
:
Check solution, find the travel for each
400/80 = 5 hr
400/100 =4 hr; 1 hr difference
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