SOLUTION: 1) 4(a-3)=3-(a+5) 2) 3z=2(z-3)+9 3) 8a-(a-7)=21 I am in an adult ed program getting my high school diploma. These three problems are the only ones that I am struggling re

Question 183802: 1) 4(a-3)=3-(a+5)
2) 3z=2(z-3)+9
3) 8a-(a-7)=21
I am in an adult ed program getting my high school diploma. These three problems are the only ones that I am struggling real hard with. We are given packets to work--and I have grasped most of the problems. These three are the ones that are not computing for me. HELP!!
Found 2 solutions by stanbon, halbren:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
1) 4(a-3)=3-(a+5)
4a - 12 = 3 - a - 5
5a -12 = -2
5a = 10
a = 2
========================
2) 3z=2(z-3)+9
3z = 2z - 6 + 9
z = 3
=======================
3) 8a-(a-7)=21
8a - a + 7 = 21
7a = 14
a = 2
===========================
Cheers,
Stan H.

Answer by halbren(10) (Show Source): You can put this solution on YOUR website!
Problem 1
First eliminate the parentheses by distribution

remember that a - sign outside a ( stands for -1 so you need to multiply everything inside the parentheses by -1
simplify

Add 12 to both sides

Add a to both sides

Divide both sides by 5

Problem 2 is similar

Subtract 2z from both sides

Problem 3 has the - sign like problem 1. You should be able to follow the same steps
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