SOLUTION: Can you please help me solve this. x-5x^1/2-36=0

Question 183520: Can you please help me solve this.
x-5x^1/2-36=0
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x-5x^1/2-36=0
-------------------
Factor:
((sqrt(x)^2-9x^(1/2)+4x^(1/2)-36 = 0
------
Factor to get:
[sqrt(x)(sqrt(x -9) + 4(sqrt(x)-9)] = 0
-----
Factor again:
(sqrt(x) - 9)(sqrt(x) + 4) = 0
sqrt(x) = 9 or sqrt(x) = -4
------
sqrt(x) cannot be -4
So If sqrt(x) = 9, x = 81
==============================
Cheers,
Stan H.
RELATED QUESTIONS
please help me solve this {{{ x^4+5x^2-36=0... (answered by checkley77)

Can you please help me solve this? I have to solve for all roots.... (answered by nerdybill)

Can you please help me solve this? I have to solve for all roots.... (answered by Earlsdon)

Can you please help me solve this Elimination equation -5x+4y=-2... (answered by ankor@dixie-net.com)

Please help me solve this equation: {{{ 5x^2+x=0... (answered by Fermat)

Hello, Please help me solve this problem, and please show all the steps if you can.... (answered by ewatrrr)

x^(-4/3)-13x^(-2/3)=-36 Can you please help me solve... (answered by stanbon)

Can some please help me solve this math problem: Solve the equation 2x^2-5x+2=0 for x. I... (answered by tutorcecilia)

Can you please help me solve this system of equations for x? 5x-2y=22 x+2y=2... (answered by nerdybill)