SOLUTION: 1/2x^2 + x -1=0 ax^2 + bx + c=0

Question 182219: 1/2x^2 + x -1=0

ax^2 + bx + c=0
Answer by jojo14344(1513) (Show Source): You can put this solution on YOUR website!

Given
, where a, b, and c are real numbers, with
Remember:
To find x-coordinate of the vertex--->

To find y-Intercept:

Vertex---->(-1,-3/2)
The Axis of symmettry is .
Solving for X-Intercepts:
By Quadratic formula:

To find Y-Intercept:

We'll mark all highlighted points in the graph:
---->
Thank you,
Jojo

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