SOLUTION: Hello Can I have help in finding the equation of the line perpendicular to the line y=3 and passing through the midpoint of the segment joining (2,4) and (-6, 10) thanks H

Question 180584: Hello
Can I have help in finding the equation of the line perpendicular to the line y=3 and passing through the midpoint of the segment joining (2,4) and (-6, 10)
thanks
H.C.
Found 2 solutions by user_dude2008, Mathtut:
Answer by user_dude2008(1862) (Show Source): You can put this solution on YOUR website!
Midpoint of (2,4) and (-6, 10):

x_mid: (2-6)/2=-4/2=-2
y_mid: (4+10)/2=14/2=7

Midpoint: (-2,7)

Any line perpendicular to y=3 is equation x=k (k is any number)

Equation is x=-2 (it's x-coordinate of midpoint)
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
sure why not....lol
:
first lets find the mid point of (2,4) and (-6,10)
:
midpoint formula((2-6)/2,(4+10)/2)
:
(-2,7) is the midpoint of these two points
:
now ordinarily we would have to find the slope of the line in question however in our case y=3 is a horizontal line 3 units above and parallel to the x axis
:
so we know the line we want is going to be a vertical line and it passes thru
(-2,7). the x coordinate is -2 therefore we know our equation is x=-2 which is a line that is 2 units to the left and parallel to the y axis.
:
there ya have it!!!!!!!!!!
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