SOLUTION: \frac{(3.7)^x (3.7)^{-1}}{(3.7)^{-4}}=(3.7)^{2}
x =
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Question 179066: \frac{(3.7)^x (3.7)^{-1}}{(3.7)^{-4}}=(3.7)^{2}
x =
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
^x (3.7)^{-1}}{(3.7)^{-4}}=(3.7)^{2})
Start with the given equation.
^x (3.7)^{-1-(-4)}=(3.7)^{2})
Subtract the exponents.
^x (3.7)^{3}=(3.7)^{2})
Combine like terms.
^x=\frac{(3.7)^{2}}{(3.7)^{3}})
Divide both sides by .
^x=(3.7)^{2-3})
Subtract the exponents.
^x=(3.7)^{-1})
Combine like terms.
Since the bases are equal, this means that the exponents are equal. So the answer is
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