SOLUTION: A chemist has 10 millimeters of a solution that contains a 30% concentration of acid. How many milliliters of pure acid must be added in order to increase the concentration to 50%.

Question 178774: A chemist has 10 millimeters of a solution that contains a 30% concentration of acid. How many milliliters of pure acid must be added in order to increase the concentration to 50%.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

I sincerely hope that you meant the chemist has 10 milliliters of solution. I'm not sure how to interpret the amount of solution when given its length.

On that assumption, let us proceed.

Let x be the amount of pure acid to be added to the existing solution, so an expression of the amount of pure acid in the mixture is

. That's because 30% of the 10 ml of solution is pure acid, and all of the x ml of acid is pure acid.

We want the resulting solution, which has a volume of 10 ml plus x ml, to have a concentration of 50%, meaning that 0.50 of the resulting solution should be pure acid. Hence

is another expression for the amount of pure acid in the mixture and is equivalent to the previous expression. Hence we can say:

Solve for x to answer your problem.

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