SOLUTION: 2x+3y=35 5x+4y=7 please solve please thank you!

Question 177885: 2x+3y=35
5x+4y=7

please solve please thank you!
Found 3 solutions by oyakhilome, jojo14344, madhan_math:
Answer by oyakhilome(1)   (Show Source): You can put this solution on YOUR website!
2x+3y=35
5x+4y=7

10x+15y=175
10x+8y =14
------------------
0 +5y=161
y=32.2
5x+4(32.2)=7
5x=121.8
x=24.4
Answer by jojo14344(1513)   (Show Source): You can put this solution on YOUR website!

Line Eqn's:
, EQN 1
, EQN 2---->, EQN 3
In EQN 1 we get,
---->
, EQN 4, subst. in EQN 2:

---->

subt. in EQN 3 or EQN 4:
We use EQN 3:

We see the graph:
----> RED Line, EQN 1; GREEN Line EQN 2
Thank you,
Jojo

Answer by madhan_math(34)   (Show Source): You can put this solution on YOUR website!
2x+3y=35
5x+4y=7
Ans:
Given equations are 2x+3y=35-------(1)
5x+4y=7 -------(2)

Equation (1)mutliplied with 4 and equation (2) mutliplied with 3.
(Since if mutliply with these numbers we get the coefficient of y term as same and we neglect y to find the x value easily)

(1) becomes, 8x + 12y = 140-----(3)
15x + 12y = 21-----(4)
Now we subtract equation (3)with (4),We have

-7x = 119
This implies,
-x = 119/7
= 17

Therefore, x = -17 -------(*)
Now we substitute this x value in any of the given equations.

2(-17)+3y = 35
-34 + 3y = 35
3y = 69 ( 35+34)
y = 23 ------ (**)
(*) and (**) are the solutions.

i.e., x = -17
y = 23 (If u like the check the answer is correct,
sub. this x and y values in any of the
given equation you will get equality.)
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