SOLUTION: Half of the greatest of 4 consecutive even integers is 5 less than the smallest. Find the integers.

Question 173312: Half of the greatest of 4 consecutive even integers is 5 less than the smallest. Find the integers.
Found 2 solutions by checkley77, Mathtut:
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
Let x, x+2, x+4, x+6 be the 4 consecutive even intergers.
(x+6)/2=x-5
x+6=2(x-5)
x+6=2x-10
x-2x=-10-6
-x=-16
x=16 answer.
Proof:
(16+6)/2=16-5
22/2=11
11=11
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
let call the integers:a,a+2,a+4,a+6
:
1/2(a+6)=a-5
:
a+6=2(a-5)
:
a+6=2a-10
:

integers are
RELATED QUESTIONS
The smallest of three consecutive even integers is 4 less than 5 times the largest.... (answered by ewatrrr)
the greatest of four consecutive even integers is 14 less than twice the smallest... (answered by stanbon)
The smallest of three consecutive even integers is 4 less than 5 times the largest. What (answered by josgarithmetic,MathTherapy)
the sum of 3 consecutive even integers is fourteen less than twice the smallest of these... (answered by geetha_rama)
I have 5 questions 1.the greater of two consecutive integers is 10 less than twice the (answered by rmromero)
the greatest of three consecutive integers is 32 less than twice the smallest integer.... (answered by CubeyThePenguin)
Thank you for your help. My question is: The greatest of four consecutive even... (answered by checkley77)
one sixth of the smallest of three consecutive even integers is three less than than one... (answered by tommyt3rd)
Find three consecutive even integers in which the greatest integer is 17 less than 2... (answered by stanbon)