SOLUTION: In the problem 5.5x -1.5y =3.5 that I tried to solve for my niece. Since there were two variables and only one equation, I thought it can`t be solved but can be simplified only. S

Question 171607: In the problem 5.5x -1.5y =3.5 that I tried to solve for my niece.
Since there were two variables and only one equation, I thought it can`t be solved but can be simplified only. So I ended up with: 2x - 1.5y=0 . But she came home with x=3, y= 4 .
To Stan and John :
this confuses me:
how did you isolate y...this way?
2 x - 1.5 y
- 1.5 y + 1.5y ( to cancel y ?) = 0

how did Y ended up on the other side of the equation

how did you get ( 2-1.5 ) x When 1.5 has no variable
Why is :
If 2x - 1.5y = 0
then y = (2/1.5)x = (4/3)x
or the same statement is
3y = 4x
--------------
_how did you get 3 & 4 ??????????? _ thanks

Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
5.5x -1.5y =3.5
To verify that the answers are correct replace x by 3 & y by 4 and solve.
5.5*3-1.5*4=3.5
16.5-6=3.5
10.5=3.5 does not match.
Therefore x=3 & y=4 are not valid answers to this equation as stated.
RELATED QUESTIONS
My niece was given an algebra problem for extra credit. I tried to solve it for her. But... (answered by Mathtut,solver91311,stanbon)

In the problem 5.5x -1.5y =3.5 that I tried to solve for my niece. Since there were two... (answered by Earlsdon)

I think that my problem falls under this topic. I am in Algebra 2 and I am stuck on this... (answered by ankor@dixie-net.com)

Below are the equations that I need assistance with... 1. 2x+y-3z=-4 2. 4x-2y+z=9 (answered by Alan3354)

I need help with this impossible problem Jake has 6 coins. Ellie has 12 coins. There (answered by josmiceli)

I am stuck on this problem! At one p.m., 1/5 of the geese fly away. At two p.m., 1/8... (answered by stanbon,ptaylor)

I do not even know were to start for this problem because i only know how to solve... (answered by Alan3354)

Hello, my name is kalea I need help whether a given ordered pair is a solution of an... (answered by jim_thompson5910)

Hello, Im seeking help regarding Graphing,Subsitution,And Elimination Next to each... (answered by Alwayscheerful)