SOLUTION: where do I begin with this problem? xsq+3x=4

Question 170017: where do I begin with this problem?
xsq+3x=4
Found 2 solutions by jim_thompson5910, midwood_trail:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Start with the given equation.

Subtract 4 from both sides.

Notice we have a quadratic equation in the form of where , , and

Let's use the quadratic formula to solve for x

Start with the quadratic formula

Plug in , , and

Square to get .

Multiply to get

Rewrite as

Add to to get

Multiply and to get .

Take the square root of to get .

or Break up the expression.

or Combine like terms.

or Simplify.

So the answers are or

Answer by midwood_trail(310) (Show Source): You can put this solution on YOUR website!
x^2+ 3x = 4
Begin by subtracting 4 from both sides and equating to zero.
x^2 + 3x - 4 = 0
We now factor the left side.
x^2 + 3x - 4 becomes (x - 1)(x + 4).
We now set each factor to zero and solve for x.
x - 1 = 0
x = 1
=========
x + 4 = 0
x = -4
=========
Final answer: x = 1 and x = -4

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