SOLUTION: How do you solve these algebraically: 1) log(x+1)+log(x-1)=log(3) 2) 5e^x+2=20 3) 4e^x=48 4) 9.5e^0.005x=19 5) 5log(base 3)x=10

Question 169148: How do you solve these algebraically:
1) log(x+1)+log(x-1)=log(3)

2) 5e^x+2=20

3) 4e^x=48

4) 9.5e^0.005x=19

5) 5log(base 3)x=10

Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Solve algebraically:
1) Apply the "product rule" () for logarithms to the left side.
Simplify the left side.
Apply the identity: If, then , so...
Add 1 to both sides.
Take the square root of both sides.
or Discard the negative solution as the log of a negative number is not a real number.
2) Divide both sides by 5.
Take the natural log of both sides.
Apply the "power rule" for logs:
Substitute

3) Divide both sides by 4.
Take the natural log of both sides.

4) Divide both sides by 9.5
Take the natural log of both sides.
Divide both sides by 0.005

5) Divide both sides by 5.
Rewrite in exponential form: means so...

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