SOLUTION: i need help with the following problems :22+4y-14=0 :4(x+5)=16 :-40-(-2x+5)=-61

Question 16819: i need help with the following problems
:22+4y-14=0
:4(x+5)=16
:-40-(-2x+5)=-61
Answer by LWahboo(3) (Show Source): You can put this solution on YOUR website!
22 + 4Y - 14 = 0

8 + 4Y = 0

4Y = - 8

Next divide by 4, the coefficient of Y.

Y = - 2

Check solutions by substituting each one in the original equation.

CHECKING SOLUTION #1: Y = -2
22 + 4Y - 14 = 0

4(-2) + 22 - 14 = 0

- 8 + 22 - 14 = 0

14 - 14 = 0

0 = 0

Solution: Y = -2
___________________________________________________
4 (X+5) = 16

Divide each side of equation by 4

(X+5) = 4

X + 5 = 4

Move constant 5 to the right.
X = - 5 + 4

Combine constants.
X = - 1
___________________________________________
- 40 - (-2X+5) = - 61

- 40 + 2X - 5 = - 61

Combine constants.
- 45 + 2X = - 61

Sort terms in decreasing powers.
2X - 45 = - 61

2X - 45 + 61 = 0

Combine constants.
2X + 16 = 0

Move constant 16 to the right.
2X = - 16

Next divide by 2, the coefficient of X.

X = - 8

Check solutions by substituting each one in the original equation.

CHECKING SOLUTION #1: X = -8
- 40 - (-2X+5) = - 61

- 40 - 21 = - 61

- 61 = - 61

Solution

Solution: X = -8
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