SOLUTION: I HAVE TO SOLVE FOR THREE VARIABLES IN THREE DIFFERENT SOLUTIONS. PLEASE HELP.
9x-y+z=-30
3x+2y-3z=-3
x-3y+2z=-12
i thought i knew how to figure it out but i have been at
Algebra.Com
Question 166430: I HAVE TO SOLVE FOR THREE VARIABLES IN THREE DIFFERENT SOLUTIONS. PLEASE HELP.
9x-y+z=-30
3x+2y-3z=-3
x-3y+2z=-12
i thought i knew how to figure it out but i have been at this well over 20 minutes so any suggestions would be greatly appreciated.
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
eliminate the same variable from two different PAIRS of equations, leaving two new equations with two unknowns
multiply 2nd eqn by -3 and add to 1st eqn __ -7y+10z=-21
multiply 3rd eqn by -3 and add to 2nd eqn __ 11y-9z=33
multiplying 1st new eqn by 11 __ -77y+110z=-231
multiplying 2n new eqn by 7 __ 77y-63z=231
adding eqns __ 47z=0 __ z=0
substituting __ 11y-9(0)=33 __ y=3
substituting __ x-3(3)+2(0)=-12 __ x-9=-12 __ x=-3
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