SOLUTION: Sally invested $4500.00. Part of it was invested at 7.5% and part of it was 6%. After one year her interest was $303.00. How much was invested at each rate?

SOLUTION: Sally invested $4500.00. Part of it was invested at 7.5% and part of it was 6%. After one year her interest was $303.00. How much was invested at each rate?

Algebra.Com

Question 159477: Sally invested $4500.00. Part of it was invested at 7.5% and part of it was 6%. After one year her interest was $303.00. How much was invested at each rate?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.075X+.06(4500-X)=303
.075X+270-.06X=303
.015X=303-270
.015X=33
X=33/.015
X=2,200 INVESTED @ 7.5%
4500-2200=2300 INVESTED @ 6%
PROOF:
.075*2200+.06*2300=303
165+138=303
303=303

RELATED QUESTIONS
Helen Weller invested $11,000. Part of it was invested a 5% interest and the rest was... (answered by josmiceli)

A total of $4500 was invested, part of it at 6% interest and the remainder at 12%. If the (answered by subudear)

Deshi invested $32,000. He invested part of it at 8% interest per year and the rest at... (answered by mananth)

Estefania invests a total of P24,000 in two accounts paying 7% and 6% annual interest,... (answered by ikleyn)

debra invested $18000.Part of it was invested at 3% annual simple interest, and the rest... (answered by mananth,robertb)

Sally invested $3000 in two parts. One part was invested at 8% interest and the second... (answered by bucky)

I dont understand this: Kendra invested $850, part of it at 9% and part of it at 12%.... (answered by checkley71)

A total of $12,000 was invested. Part of the money was invested at 4% and the rest... (answered by checkley79)

Solve this application problem using a system of equations: $4400 is invested, part of it (answered by ikleyn)