SOLUTION: The length of a rectangular playing field is 5 meters less than twice its width. if 230 meters of fencing goes around the field, find the dimensions of the field.

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Question 158976: The length of a rectangular playing field is 5 meters less than twice its width. if 230 meters of fencing goes around the field, find the dimensions of the field.
Found 2 solutions by checkley77, Electrified_Levi:
Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!
L=2W-5
2W+2(W-5)=230
2W+2W-10=230
4W=230+10
4W=240
W=240/4
W=60 METERS FOR THE WIDTH.
L=2*60-5
L=120-5
L=115 METERS FOR THE LENGTH.
PROOF:
2*60+2(60-5)=230
120+2*55=230
120+110=230
230=230

Answer by Electrified_Levi(103)   (Show Source): You can put this solution on YOUR website!
Hi, Hope I can help
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The length of a rectangular playing field is 5 meters less than twice its width. if 230 meters of fencing goes around the field, find the dimensions of the field.
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First we have to find variables for length and width
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The length of a rectangular playing field is 5 meters less than twice its width.
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We can name the width "x"
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The length of a rectangular playing field is 5 meters less than twice its width, if the width is "x", and the length is 5 meters less than twice the width, this is how you right the length, , width = "x" =
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The length =
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The width =
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Since 230 meters of fencing goes around the field, we are trying to find the Perimeter of the field
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The length =
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The width =
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The Perimeter of a Rectangle is =
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They give us the Perimeter, 230 meters, so we can replace "Perimeter" with "230"
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=
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Since the width = , and the length = , we can replace "width" and "length" with our variables
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= , now just solve for "x"
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We will get rid of the parentheses, and use distribution
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= = = (Since the "5" is negative the number will be negative)
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Add like terms
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= =
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We will move (-10) to the right side
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= = , To solve "x" we will divide each side by "6"
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= = =
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x = "40", we can check by replacing "x" with "40" in our equation
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= = = = = ( True )
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x = "40"
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Our width and length in variable form were:(Just replace "x" with "40" in our equations)
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The length = = = = 75
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The width = = 40
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Since the unit is the meter, our answers would be
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The Length = 75 meters
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The Width = 40 meters
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Hope I helped, Levi

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