SOLUTION: The lenght of a rectangle is 6 more feet than twice the width. If the perimeter is 24 ft., what are the dimensions?

Question 153085: The lenght of a rectangle is 6 more feet than twice the width. If the perimeter is 24 ft., what are the dimensions?
Answer by Electrified_Levi(103) (Show Source): You can put this solution on YOUR website!
Hi, Hope I can help,
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The length of a rectangle is 6 more feet than twice the width. If the perimeter is 24 ft., what are the dimensions?
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First, we have to find out the variables, The length of a rectangle is 6 more feet than twice the width. If the perimeter is 24 ft., what are the dimensions?
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We see that the width is "x", the length is 6 more feet than twice the width, or "2x + 6", now we will place the variables into a formula
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the Perimeter formula for a rectangle =
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We can replace the width and length into the formula, our Perimeter = 24 feet
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=
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We will use distribution
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=
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We will add like terms
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= =
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We will move the "12" over to the right side
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=
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We will divide each side by "6"
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x = 2
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We now know the width, since the width = "x"
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width = "x", or "2"
length = (2x+6), or (2(2) + 6), or (4+6), or "10"
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width = "2" feet
length = "10" feet
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"10" is 6 more feet than twice the width(2)
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We can check by replacing "x" in our equation ( x = 2)
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=
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=
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=
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=
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= (True)
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Length = 10 feet
Width = 2 feet
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Hope I helped, Levi
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