SOLUTION: Consider a rational function whose denominator is -x^2 + 4x + ½. What is the maximum number of vertical asymptotes it may have?
a. 2
b. 4
c. ½
d. The denominator defines the fu
Algebra.Com
Question 153034: Consider a rational function whose denominator is -x^2 + 4x + ½. What is the maximum number of vertical asymptotes it may have?
a. 2
b. 4
c. ½
d. The denominator defines the function’s zeroes, not its vertical asymptotes.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Notice how the degree of -x^2 + 4x + ½ is 2. So there are at most 2 zeros. This means that there are at most 2 vertical asymptotes.
RELATED QUESTIONS
Please help with the following:
Consider a rational function whose numerator is {{{... (answered by stanbon)
The maximum number of vertical asymptotes a rational function can have is infinite.
(answered by stanbon)
What is the maximum number of horizontal asymptotes that the graph of a rational function (answered by ikleyn)
Let f(x) be a rational function such that when f(x) is in reduced form, the numerator and (answered by MathLover1)
consider g(x)=x^3+4x; what is the maximum number of zeroes it can have?
consider... (answered by stanbon)
What is an equation of a rational function without any "holes", vertical asymptotes, or... (answered by Fombitz)
Consider g(x) = x^3 + 4x; what is the maximum number of zeroes it can have?
a. 2
b. (answered by jim_thompson5910)
Consider g(x) = x^3 + 4x; what is the maximum number of turns it can have?
a. 2
b. 1... (answered by edjones)
Consider g(x)=x^3+4x; what is the maximum number of zeroes it can have?
a. 2
b. 1
c. (answered by Alan3354)