SOLUTION: How many positive real solutions are there in f(x) = x^4 + 4x^3 + 6x^2 + 4x � 1 Apply Descartes' Rule of Signs. a. 1 b. 1 or 2 c. 4 or 2 d. 2 or 0

Question 152871: How many positive real solutions are there in f(x) = x^4 + 4x^3 + 6x^2 + 4x � 1
Apply Descartes' Rule of Signs.
a. 1
b. 1 or 2
c. 4 or 2
d. 2 or 0
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Count the sign changes of

From to , there is no change in sign

From to , there is no change in sign

From to , there is no change in sign

From to , there is a sign change from positive to negative

So there is 1 sign change for the expression .

So there are 1 positive zeros

So the answer is a) 1
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