SOLUTION: Consider g(x) = x^n + 4x^n - 1; what is the maximum number of turns it can have? @ The maximum number of turns = n – 1. a. n – 2 b. n – 1 c. n d. n + 1

Algebra.Com
Question 152865: Consider g(x) = x^n + 4x^n - 1; what is the maximum number of turns it can have?
@ The maximum number of turns = n – 1.
a. n – 2
b. n – 1
c. n
d. n + 1

Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
b.
RELATED QUESTIONS

Consider g(x) = x^3 + 4x; what is the maximum number of turns it can have? a. 2 b. 1... (answered by edjones)
Consider polynomial {{{g(x) = x^n + 4x^(n-1)}}}; what is its maximum number of zeroes? @... (answered by Edwin McCravy)
Consider polynomial g(x) = x^n + 4x; what is its maximum number of zeroes? @ The maximum... (answered by nabla)
consider g(x)=x^3+4x; what is the maximum number of zeroes it can have? consider... (answered by stanbon)
Consider g(x) = x^3 + 4x; what is the maximum number of zeroes it can have? a. 2 b. (answered by jim_thompson5910)
Consider g(x)=x^3+4x; what is the maximum number of zeroes it can have? a. 2 b. 1 c. (answered by Alan3354)
f(n)=1^2+2^2+3^2+...+n^2 it turns out that f is a polynomial of degree x in n. Figure out (answered by venugopalramana)
what is the maximum number of diagonals can be drawn in a n-sided polygon? (answered by Edwin McCravy)
g(x)= x^3+4 what is the max number of zeros it can have and the max numberof... (answered by SAT Math Tutor)