SOLUTION: The perimeter of a rectangle is 22m. The lenght is 5 more than twice the width. Find the dimesions.

Question 151545: The perimeter of a rectangle is 22m. The lenght is 5 more than twice the width. Find the dimesions.
Answer by iluvbuilding429(41) (Show Source): You can put this solution on YOUR website!
The perimeter of a rectangle is 22m. The lenght is 5 more than twice the width. Find the dimesions.
Use the formula:

Plug in your amount for the perimeter:

Since the length is 5 more than twice the width, L=2w+5. So, replace L with 2w+5:

Use the distributive property for the the parentheses:

Rearrange the terms so that you will be able to add the like terms:

Add the like terms:

Subtract 10 from both sides:

Divide both sides by 6:

This means the width is 2. To find the length (which is 2w+5), plug in the 2 for w.

Multiply:

Add:

So, the length is 9, and the width is 2.

-iluvbuilding429
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