SOLUTION: What are the zero(s) for this equation:
4(x+6)^2-8=-4
a)x={-5}
b)x={-5,-7}
c)x={-5,0}
d)x={5,-7}
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Question 146281: What are the zero(s) for this equation:
4(x+6)^2-8=-4
a)x={-5}
b)x={-5,-7}
c)x={-5,0}
d)x={5,-7}
Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website!
4(x+6)^2-8=-4
then 4(x+6)^2=4
then (x+6)^2=1
then x+6=1 or x+6=-1
then x=-5 or x=-7
then
option b) is the correct
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