SOLUTION: Three times the first of two numbers decreased by the second number equals 9. Twice the first number increased by the second number equals 11. Find the two numbers. I need a system

Question 14584: Three times the first of two numbers decreased by the second number equals 9. Twice the first number increased by the second number equals 11. Find the two numbers. I need a system of equations to solve the problem.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let x = the first number and y = the second number. You can write:
3x - y = 9 Three times the 1st number (3x) decreased by the 2nd number (-y) = 9
2x + y = 11 Two times the 1st number (2x) increased by the 2nd number (+y) = 11
There are the two equations you need. Can you take it from here?
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