SOLUTION: Hi. I'm stuck on a word problem. Could someone please help me? Thank you in advance!! In 1993 the life expectancy of males was 63.7 years. In 1999, it was 66.8. Let E represent

Question 144491: Hi. I'm stuck on a word problem. Could someone please help me? Thank you in advance!!
In 1993 the life expectancy of males was 63.7 years. In 1999, it was 66.8. Let E represent the life expectancy in years and let t represent number of years since 1993.
I need to write a linear equation that fits the data. E(t)= ___t + ___
Also I need to use the function to predict the life expectancy of males in 2007.
E(14)=____
Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!
You are given two points, so first find the slope between them.
slope = (y2 - y1)/(x2 - x1)
slope = (66.8 - 63.7)/(1999 - 1993)
slope = 3.1/6 = 0.516
is an equation for a line that represents the life expectancy of a males, where t is the number of years starting at 1993.
So, using this equation, we see that in 1193, t = 0 (year - 1993)
This yields 63.7
In the year 1999, t = (1999-1993) = 6
E(6) = 0.516(6) + 63.7 = 66.8
Now let's assume the same model is OK through 2007. t = (2007 - 1993) = 14
E(14) = 0.516*14 + 63.7
E(14) = 70.924
Make sense?

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