SOLUTION: What are the zero(s) for this equation:
4(x+6)^2 - 8 = -4
a. x = {-5}
b. x = {-5,-7}
c. x = {-5,0}
d. x = {5,-7}
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Question 144071: What are the zero(s) for this equation:
4(x+6)^2 - 8 = -4
a. x = {-5}
b. x = {-5,-7}
c. x = {-5,0}
d. x = {5,-7}
Answer by nabla(475) (Show Source): You can put this solution on YOUR website!
Divide both sides by 4, giving:
(x+6)^2-2=-1
(x+6)^2=1
x+6=+/- 1
x=-6+/-1
-6+1=-5
-6-1=-7
Giving (b) as the answer.
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