SOLUTION: Let R(x)=x^3-2x^2-7/x^6-2x^5+6x^2-4. How many vertical asymptotes are possible? a. 3 b. 2 c. 6 d. 5

Question 143968: Let R(x)=x^3-2x^2-7/x^6-2x^5+6x^2-4. How many vertical asymptotes are possible?
a. 3
b. 2
c. 6
d. 5
Answer by nabla(475) (Show Source): You can put this solution on YOUR website!
Vertical asymptotes are made by places where we would divide by zero.
For your problem,
x^6-2x^5+6x^2-4=0 will give possible asymptotes.
How many zeros does x^6-2x^5+6x^2-4 have??? The degree of the polynomial, namely 6, is the possible number of roots. Thus c would be your answer.
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