SOLUTION: Find two positive real numbers that differ by 2 and have a product of 10.
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Question 142735: Find two positive real numbers that differ by 2 and have a product of 10.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
X(X+2)=10
X^2+2X-10=0
USING THE QUADRATIC EQUATION WE GET:
X=(-2+-SQRT[262-4*1*-10])/2*1
X=(-2+-SQRT[4+40])/2
X=9-2+-SQRT44)/2
X=(-2+-6.63325)/2
X=(-2+6.63325)/2
X=4.63325/2
X=2.3166 ANSWER.
2.3166+2=4.3166 ANSWER.
PROOF:
2.3166*4.3166=10
10~10
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