SOLUTION: Factor the following:
r(s) = 2s^2 + st - 2s -t
a. r(s) = 2(s+1)(s-1)
b. r(s) = (2s-t)(s-1)
c. r(s) = (2s+1)(s-1)
d. This cannot be factored; it's prime
I selected d
Algebra.Com
Question 141203: Factor the following:
r(s) = 2s^2 + st - 2s -t
a. r(s) = 2(s+1)(s-1)
b. r(s) = (2s-t)(s-1)
c. r(s) = (2s+1)(s-1)
d. This cannot be factored; it's prime
I selected d.
Found 2 solutions by nabla, vleith:
Answer by nabla(475) (Show Source): You can put this solution on YOUR website!
r(s) = 2s^2 + st - 2s -t
r(s) = s(2s + t) - 1 (2s + t) (Factoring and grouping)
r(s) = (s - 1)(2s + t) (Factor out (2s+t leaving the answer)
Your answer is c.
Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!
Given:
So I am going with e. Which is c with a typo :-D
RELATED QUESTIONS
Completely factor the following: r(s) = 2s2 + st – 2s + t
@ Normally, this would be... (answered by Edwin McCravy)
Completely factor the following: r(s) = 2s^2 + st – 2s + t
@ Normally, this would be... (answered by checkley77)
r - s + 2t = -1
2r + 2s - t = 0
r + s = 5
2r + 2t = 4 (answered by Alan3354)
solve for s
A=1/5pi r squared... (answered by lynnlo,Alan3354)
Let r, s, and t be solutions of the equation {{{x^3 + 2x^2 - 5x + 15 = 0}}}.
Compute... (answered by CPhill,ikleyn,Edwin McCravy)
solve... (answered by richard1234)
Consider the following formula:
2S+T^2
R= ------
3
Solve for... (answered by ankor@dixie-net.com)
If r^2s^-3t^1/2=0 which of the following CANNOT be true?
I. r = 0
II. s = 0
(answered by stanbon,MathLover1)
r = 2s - 8 What is... (answered by elima)